Tuesday, August 2, 2011

Math meeting 08-02-2011-fractions, Proportions, inverse relations

Hi,

we talked about direct and inverse proportion.

We also did part of the problems: we will continue to finish it next meeting

This  problem set:
1,We review cross multiplication
2, Children seem to forget the concept of the function y=f(x) 
Please review

Next meeting:
08-04-2011 Am10:00-12:00
We will continue to finish and correct the problem set

Friday, July 29, 2011

Math meeting 7-28-2011

Hi,
We have reviewed (07-28-2011)
Next math meeting;
08-02-2011 Am 10:00-12:00
We will discuss problem solving strategies
Fraction, direct and inverse fraction

Direct and Inverse Proportion

Two types of proportions
Direct proportion;
Y=f(x)=kx  k is a constant
or Y/X=k
Y and X are direct proportion
The more X is, the more Y is
ex: buy one book costs $2, two books costs $4, 3 books costs $6.......
(given k=2, when x=1then y-=2,x=2then y=4 ,x=3 then y=6.............)
the more  x is, the more y is
the more the books, the more  the cos is
x and y are direct proportion (books and cost are direct proportion)

Inverse proportion:
Y=f(x)=k /X             k is a constant
or XY=k
X and Y are inverse proportion
The more X is, The less Y is
ex: D=RT
if D is a constant.
The faster the rate is , the less  the time it will take
EX1: k=xy (D=RT)                                                                      k=xy (D=RT)
 Given 120 miles, rate at 30 mph, it takes 4hours(given k=120   120=30x4)
                           rate at 60 mph, it takes 2 hours(given k=120, 120=60x2)
                          rate ate 120 mph, it takes 1hour(given k=120  120=120x1)
                       
The more x is, the less y is (k=xy)
The more R is, the less T is (D=RT)
x and y are inverse proportion (R and T are inverse proportion)

Ex2: It takes 10 workers and works 100 hours to finish a project(Given k=1000=10x100 )
        It takes 20 workers and works  50 hours to finish a project (k=1000, 1000=20x50)
        It takes 40 workers and work 25 hours to finish a project   (k=1000, 1000=40x25)

Problem Solving Strategy:
Step1: to recognize if it is direct or inverse proportion
Step2: If it is direct proportion: y=f(x)=kx
          If It is inverse proportion: y=f(x)=k/x
Step3: find k=? and put the value in the known variable, and solve the unknown variable.

Q1, For the function f , y=f(x) is inversely proportional to x, when x>0.  If f(3) =6, what is the value of f(2)?

Since it is  inversely proportional- xy=k, y=k/x
 y=f(x)=f(3) =k/3=6, so k=18
f(2)=k/x=18/2=9


Q2, If y is directly proportional to x square and y=1/8 when x=1/2 what is the positive value of x when y=9/2
Since it is directly proportional , y=k(x)(x)
1/8=k(1/4), so k=1/2
9/2=k(x)(x)=1/2(x)(x)
so x=3


Q3, If 5 chickens lay 5 eggs in 5 days. How many eggs will 25 chickens lay in 25 days?
The more chicken, the more eggs, and the less days
Chicken(C) and eggs (E)are direct proportional, and chicken(C) and days(D) are inverse 
proportional ,
Therefore, k=CD/E , k=(5x5)/5=5
k=5=(25x25)/D
D= 125


More Study:

Math Word Problem of the Day

Quadrilaterals




More Study:
Quadrlaterals

Tuesday, July 26, 2011

Math meeting 07-26-2011-circle-review

Hi,

We have review properties of a circle we have learned.

I, Vocabularies and definition
http://lin-mathclub.blogspot.com/2011/07/circle-some-definition.html

II, Chords and Circles
http://lin-mathclub.blogspot.com/2011/07/circle-arc-and-chord.html

III, Tangent line
http://lin-mathclub.blogspot.com/2011/07/circle-tangent-line.html

IV, Circle and angles: Central angles and Inscribed angles
http://lin-mathclub.blogspot.com/2011/07/circle-arc-and-chord.html

V, The Alternate Segment Theorem
http://lin-mathclub.blogspot.com/2011/07/alternate-segment-theorem.html

VI, Angles and Circles
http://lin-mathclub.blogspot.com/2011/07/circle-circle-and-angles.html

VII, Chords, Secants, Tangents in Circles-Power of a point
http://lin-mathclub.blogspot.com/2011/07/circle-power-of-point.html


More Study:


Multiple Choice Practice - Circles 
Next meeting :
07-28-2011 Am10:00-12:00

We will discuss Geometry-Quadrilateral Family

Monday, July 25, 2011

Math meeting 07-25-2011

Hi,

We discussed circle-power of a point


http://lin-mathclub.blogspot.com/2011/07/circle-power-of-point.html.

Next meeting:

We will review all  properties of a circle we have learned

Please print out the attachments  and bring to the meeting.

Meeting time:
07-26-2011 Am 10:00-12:00

Thursday, July 21, 2011

Math meeting 07-21-2011

Hi,

We have discussed 
1,Circle-angles formed by intersecting chords,secants-tangents-arcs-angle
2, Problem solving : word problems
Homework
Angles in a circle
Next Meeting
07-25-2011
10:00-12:00AM
Please print the attachments and bring to the meeting

Tuesday, July 19, 2011

Math meeting 07-19-2011

Hi,
We have discussed the attachment 3-Circle-other angles and circle
Please print out the first two attachments (if you did not print last time)

Next meeting
07-21-2011
10:00am- 12:00

Monday, July 18, 2011

Math meeting 7-18-2011

We have discussed the alternate segment theorem


Homework: please finish the practice part

The intersection of a tangent and chord ( The alternate segment theorem)


Next Meeting:
07-19-2011 AM10:00-12:00
We are going to discuss
1,Review: Circle,   
2,angles in a circle

Tuesday, July 12, 2011

The Alternate Segment Theorem




More Study:
Alternate segment theorem
Proof: http://www.absorblearning.com/media/attachment.action?quick=l9&att=1522

Math meeting 7-12-2011

Hi,

We have discussed
1,angles in a circle-central , inscribed angles
2,triangle exterior angle theorem and proportion theorem

Homework:

Next meeting:
AM 10:00-12:00 07-13-2011
1, Review:Circle, similar triangle
2, The Alternate Segment Theorem